Click “Find the tail area,” enter a score of .50, and press the enter key or click on the “Illustrate” button. \u00a0Here are the results:<\/p>\n You can see that the area greater than a z score of .50 is equal to .3085. \u00a0Now, click the other options to see what results you will get. \u00a0Also, explore the\u00a0Image Options<\/strong>. \u00a0You can resize this plot, change the title or labels, copy it to your clipboard, and save it to a file.<\/p>\n Which two z scores will define the central 95% of a standard normal distribution?<\/p>\n Pull down the Analysis Options<\/strong> menu, and choose\u00a0Find Scores in the Normal Distribution<\/strong>. \u00a0Click “Find scores for the central proportion,” enter .95 as your score, and then press enter or click the illustrate button. \u00a0Here are the results:<\/p>\n You can see that z scores of -1.96 and +1.96 define the central 95% of a standard normal distribution. \u00a0Now, click the other options here to see the other types of results that you can produce.<\/p>\n You are working with a normal distribution of IQ scores, which have a mean of 100 and a standard deviation of 15. \u00a0What percentage of scores will be found between a score of 115 and a score of 130?<\/p>\n Press the “Reset” button. \u00a0Now, pull down the\u00a0Analysis Options<\/strong> menu, and choose\u00a0Some other Normal Distribution<\/strong>. \u00a0Also, click\u00a0the “Find the area between two scores” option. \u00a0You will have to enter four values:<\/p>\n Enter a mean of 100, and a standard deviation of 15. \u00a0Then, enter your two scores — enter 115 for the first one and 130 for the second (note that you must enter the lower score as your first score). \u00a0Now, press enter or click “illustrate.” \u00a0Here are the results.<\/p>\n![\"norm1\"](\"https:\/\/sites.berry.edu\/vbissonnette\/wp-content\/uploads\/sites\/21\/2016\/07\/norm1.png\")
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\nHomework Problem #2<\/h3>\n
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\nHomework Problem #3<\/h3>\n
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